Q. Under isothermal condition, a gas at 300 K expands from 0.1L to 0.25L against a constant external pressure of 2 bar. The work done by the gas is : [Given that 1L bar = 100 J]
A) -30 J
B) 5kJ
C) 25 J
D) 30 J
Explanation
[Solution] $w = -P_{ext}\Delta V = -2 \times (0.25 - 0.1) = -0.3$ L bar = -30 J. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.