Q. A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :
A) $C_2A_3$
B) $C_3A_2$
C) $C_3A_4$
D) $C_4A_3$
Explanation
[Solution] Octahedral voids = number of anions, so C : A = 0.75 : 1 = 3 : 4, giving $C_3A_4$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.