Q. If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by :
A) t = 0.693/k
B) t = 6.909/k
C) t = 4.606/k
D) t = 2.303/k
Explanation
[Solution] $t = \frac{2.303}{k}\log\frac{100}{1} = \frac{4.606}{k}$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.