Q. Which is the correct thermal stability order for $H_2E$ (E = O, S, Se, Te and Po) ?
A) $H_2S < H_2O < H_2Se < H_2Te < H_2Po$
B) $H_2O < H_2S < H_2Se < H_2Te < H_2Po$
C) $H_2Po < H_2Te < H_2Se < H_2S < H_2O$
D) $H_2Se < H_2Te < H_2Po < H_2O < H_2S$
Explanation
[Solution] The H-E bond weakens down the group, so thermal stability decreases from $H_2O$ to $H_2Po$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.