An alkene "A" on reaction with $O_3$ and $Zn-H_2O$ gives propanone and ethanal in equimolar ratio. Addition of HCl to alkene "A" gives "B" as the major product. The structure of product "B" is :

Question

Dr. Abubacker · Accepted Answer

[Solution] A is $(CH_3)_2C=CH-CH_3$ (2-methylbut-2-ene). Markovnikov addition of HCl gives $(CH_3)_2CCl-CH_2CH_3$ (2-chloro-2-methylbutane). Answer (3).

Q. An alkene "A" on reaction with $O_3$ and $Zn-H_2O$ gives propanone and ethanal in equimolar ratio. Addition of HCl to alkene "A" gives "B" as the major product. The structure of product "B" is :

Explanation

Reviewed by Dr. Abubacker

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