Q. The major product of the following reaction is : Phthalic acid ($C_6H_4(COOH)_2$, benzene-1,2-dicarboxylic acid) + $NH_3$ $\xrightarrow{strong\ heating}$ ?
A) 2-Carbamoylbenzoic acid ($C_6H_4(COOH)(CONH_2)$)
B) Phthalimide ($C_6H_4(CO)_2NH$)
C) Anthranilic acid ($C_6H_4(COOH)(NH_2)$)
D) o-Phenylenediamine ($C_6H_4(NH_2)_2$)
Explanation
[Solution] Phthalic acid with ammonia on strong heating forms ammonium phthalate, then the amide, which cyclises to phthalimide. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.