Q. For the chemical reaction $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$ the correct option is :
A) $-\frac{1}{3}\frac{d[H_2]}{dt} = -\frac{1}{2}\frac{d[NH_3]}{dt}$
B) $-\frac{d[N_2]}{dt} = 2\frac{d[NH_3]}{dt}$
C) $-\frac{d[N_2]}{dt} = \frac{1}{2}\frac{d[NH_3]}{dt}$
D) $3\frac{d[H_2]}{dt} = 2\frac{d[NH_3]}{dt}$
Explanation
[Solution] Rate $= -\frac{d[N_2]}{dt} = -\frac{1}{3}\frac{d[H_2]}{dt} = \frac{1}{2}\frac{d[NH_3]}{dt}$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.