Q. Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost by the colliding body A is :
A) $\frac{1}{9}$
B) $\frac{8}{9}$
C) $\frac{4}{9}$
D) $\frac{5}{9}$
Explanation
[Solution] Fraction transferred $= \frac{4m_1m_2}{(m_1+m_2)^2} = \frac{4 \times 4m \times 2m}{(6m)^2} = \frac{8}{9}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.