Q. The displacement of a particle executing simple harmonic motion is given by $y = A_0 + A\sin\omega t + B\cos\omega t$. Then the amplitude of its oscillation is given by :
A) $A_0 + \sqrt{A^2 + B^2}$
B) $\sqrt{A^2 + B^2}$
C) $\sqrt{A_0^2 + (A+B)^2}$
D) A + B
Explanation
[Solution] $A_0$ only shifts the mean position; the amplitude is $\sqrt{A^2 + B^2}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.