Q.
A soap bubble, having radius of 1 mm, is blown from a detergent solution having a surface tension of $2.5 \times 10^{-2}$ N/m. The pressure inside the bubble equals at a point $Z_0$ below the free surface of water in a container. Taking g = 10 $m/s^2$ density of water = $10^3$ kg/$m^3$, the value of $Z_0$ is :
A) 100 cm
B) 10 cm
C) 1 cm
D) 0.5 cm
Explanation
[Solution] Excess pressure $= \frac{4T}{r} = \frac{4 \times 2.5 \times 10^{-2}}{10^{-3}} = 100$ Pa $= \rho gZ_0$, so $Z_0 = 0.01$ m = 1 cm. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.