A copper rod of 88 cm and an aluminum rod of unknown length have their increase in length independent of increase in temperature. The length of aluminum rod is : ($\alpha_{Cu} = 1.7 imes 10^{-5}$ $K^{-1}$ and $\alpha_{Al} = 2.2 imes 10^{-5}$ $K^{-1}$)

Question

A copper rod of 88 cm and an aluminum rod of unknown length have their increase in length independent of increase in temperature. The length of aluminum rod is : ($\alpha_{Cu} = 1.7 	imes 10^{-5}$ $K^{-1}$ and $\alpha_{Al} = 2.2 	imes 10^{-5}$ $K^{-1}$)

Dr. Abubacker · Accepted Answer

[Solution] $L_{Cu}\alpha_{Cu} = L_{Al}\alpha_{Al}$, so $L_{Al} = \frac{88 	imes 1.7}{2.2} = 68$ cm. Answer (4).

Q. A copper rod of 88 cm and an aluminum rod of unknown length have their increase in length independent of increase in temperature. The length of aluminum rod is : ($\alpha_{Cu} = 1.7 \times 10^{-5}$ $K^{-1}$ and $\alpha_{Al} = 2.2 \times 10^{-5}$ $K^{-1}$)

Explanation

Reviewed by Dr. Abubacker

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