Q. When a block of mass M is suspended by a long wire of length L, the length of the wire become (L + l). The elastic potential energy stored in the extended wire is :
A) Mgl
B) MgL
C) $\frac{1}{2}Mgl$
D) $\frac{1}{2}MgL$
Explanation
[Solution] Elastic PE $= \frac{1}{2} \times$ force $\times$ extension $= \frac{1}{2}Mgl$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.