A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :

Question

Dr. Abubacker · Accepted Answer

[Solution] $W = \int_0^1(20 + 10y)dy = 20 + 5 = 25$ J. Answer (3).

Q. A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :

Explanation

Reviewed by Dr. Abubacker

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