Q.
The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe is
A) 12.5 cm
B) 8 cm
C) 13.2 cm
D) 16 cm
Explanation
[Solution] $\frac{v}{2L_o} = \frac{3v}{4L_c}$, so $L_o = \frac{2}{3}L_c = 13.3$ cm ≈ 13.2 cm. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.