Q. A carbon resistor of (47 ± 4.7) kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be
A) Yellow - Green - Violet - Gold
B) Yellow - Violet - Orange - Silver
C) Violet - Yellow - Orange - Silver
D) Green - Orange - Violet - Gold
Explanation
[Solution] 47 × $10^3$ Ω with ±10%: yellow (4), violet (7), orange ($10^3$), silver (10%). Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.