Q. A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 $m/s^2$ at a distance of 5 m from the mean position. The time period of oscillation is
A) 2 s
B) $\pi$ s
C) $2\pi$ s
D) 1 s
Explanation
[Solution] $\omega^2 = a/x = 4$, $\omega = 2$ rad/s, $T = 2\pi/\omega = \pi$ s. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.