Q. An inductor 20 mH, a capacitor 100 μF and a resistor 50 Ω are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is
A) 2.74 W
B) 0.43 W
C) 0.79 W
D) 1.13 W
Explanation
[Solution] $X_L = 6.28$ Ω, $X_C = 31.85$ Ω, $Z = \sqrt{50^2 + 25.57^2} = 56.2$ Ω; $I_{rms} = 7.07/56.2 = 0.126$ A; $P = I^2R = 0.79$ W. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.