Q. The power radiated by a black body is P and it radiates maximum energy at wavelength, $\lambda_0$. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength $\frac{3}{4}\lambda_0$, the power radiated by it becomes nP. The value of n is
A) $\frac{256}{81}$
B) $\frac{4}{3}$
C) $\frac{3}{4}$
D) $\frac{81}{256}$
Explanation
[Solution] Wien: T ∝ 1/λ, so T becomes 4T/3; P ∝ $T^4$ gives n = 256/81. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.