Q. A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. $H_2SO_4$. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
A) 2.8
B) 3.0
C) 1.4
D) 4.4
Explanation
[Solution] HCOOH (0.05 mol) gives 0.05 mol CO; $H_2C_2O_4$ (0.05 mol) gives 0.05 mol CO + 0.05 mol $CO_2$. KOH absorbs $CO_2$ and water, leaving 0.1 mol CO = 2.8 g. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.