Q. The compound $C_7H_8$ undergoes the following reactions : $C_7H_8 \xrightarrow{3Cl_2/\Delta} A \xrightarrow{Br_2/Fe} B \xrightarrow{Zn/HCl} C$ The product 'C' is
A) 3-bromo-2,4,6-trichlorotoluene
B) $o$-bromotoluene
C) $m$-bromotoluene
D) $p$-bromotoluene
Explanation
[Solution] Side-chain chlorination gives $C_6H_5CCl_3$; the meta-directing $-CCl_3$ group sends Br to the meta position; Zn/HCl reduces $-CCl_3$ to $-CH_3$, giving m-bromotoluene. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.