Q. Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations : a. 60 mL $\frac{M}{10}$ HCl + 40 mL $\frac{M}{10}$ NaOH b. 55 mL $\frac{M}{10}$ HCl + 45 mL $\frac{M}{10}$ NaOH c. 75 mL $\frac{M}{5}$ HCl + 25 mL $\frac{M}{5}$ NaOH d. 100 mL $\frac{M}{10}$ HCl + 100 mL $\frac{M}{10}$ NaOH pH of which one of them will be equal to 1 ?
A) d
B) a
C) b
D) c
Explanation
[Solution] (c): 15 - 5 = 10 mmol $H^+$ in 100 mL = 0.1 M, pH = 1. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.