Q. A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of resulting system :

A) increases by a factor of 4
B) decreases by a factor of 2
C) remains the same
D) increases by a factor of 2
Explanation

[Solution] Charge Q is shared over 2C: $U' = Q^2/(4C) = U/2$. Answer (2).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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