Q. Two cars moving in opposite directions approach each other with speed of 22 m/s and 16.5 m/s respectively. The driver of the first car blows a horn having a frequency 400 Hz. The frequency heard by the driver of the second car is [velocity of sound 340 m/s] :

A) 350 Hz
B) 361 Hz
C) 411 Hz
D) 448 Hz
Explanation

[Solution] $f' = 400 \times \frac{340 + 16.5}{340 - 22} = 400 \times \frac{356.5}{318} \approx 448$ Hz. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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