Q. A long solenoid of diameter 0.1 m has $2 \times 10^4$ turns per meter. At the centre of the solenoid, a coil of 100 turns and radius 0.01 m is placed with its axis coinciding with the solenoid axis. The current in the solenoid reduces at a constant rate to 0A from 4 A in 0.05 s. If the resistance of the coil is $10\pi^2$ Ω, the total charge flowing through the coil during this time is :

A) 32$\pi$ μC
B) 16 μC
C) 32 μC
D) 16$\pi$ μC
Explanation

[Solution] $Q = \frac{N\Delta\phi}{R} = \frac{100 \times \mu_0 n I \pi r^2}{R} = \frac{100 \times 4\pi \times 10^{-7} \times 2 \times 10^4 \times 4 \times \pi \times 10^{-4}}{10\pi^2} = 32$ μC. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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