Q. The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is :
A) $\frac{h}{\sqrt{mkT}}$
B) $\frac{h}{\sqrt{3mkT}}$
C) $\frac{2h}{\sqrt{3mkT}}$
D) $\frac{2h}{\sqrt{mkT}}$
Explanation
[Solution] KE = $\frac{3}{2}kT$, so $p = \sqrt{3mkT}$ and $\lambda = h/\sqrt{3mkT}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.