A carnot engine having an efficiency of $\frac{1}{10}$ as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :

Question

Dr. Abubacker · Accepted Answer

[Solution] $\beta = \frac{1 - \eta}{\eta} = 9$, so $Q_2 = \beta W = 90$ J. Answer (2).

Q. A carnot engine having an efficiency of $\frac{1}{10}$ as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :

Explanation

Reviewed by Dr. Abubacker

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