Q. Name the gas that can readily decolourise acidified $KMnO_4$ solution :
A) $CO_2$
B) $SO_2$
C) $NO_2$
D) $P_2O_5$
Explanation
[Solution] $SO_2$ is a reducing agent and reduces $MnO_4^-$ to colourless $Mn^{2+}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.