Q. The equilibrium constants of the following are : $N_2 + 3H_2 \rightleftharpoons 2NH_3$ $K_1$ $N_2 + O_2 \rightleftharpoons 2NO$ $K_2$ $H_2 + \frac{1}{2}O_2 \rightarrow H_2O$ $K_3$ The equilibrium constant (K) of the reaction : $2NH_3 + \frac{5}{2}O_2 \overset{K}{\rightleftharpoons} 2NO + 3H_2O$, will be :
A) $K_1K_3^3/K_2$
B) $K_2K_3^3/K_1$
C) $K_2K_3/K_1$
D) $K_2^3K_3/K_1$
Explanation
[Solution] Target = (reverse of 1) + (2) + 3 × (3), so $K = K_2K_3^3/K_1$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.