Q. Pick out the correct statement with respect to $[Mn(CN)_6]^{3-}$ :
A) It is $sp^3d^2$ hybridised and octahedral
B) It is $sp^3d^2$ hybridised and tetrahedral
C) It is $d^2sp^3$ hybridised and octahedral
D) It is $dsp^2$ hybridised and square planar
Explanation
[Solution] $Mn^{3+}$ ($d^4$) with strong-field $CN^-$ pairs electrons, leaving two empty 3d orbitals: $d^2sp^3$, octahedral. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.