Q. In Hardy-Weinberg equation, the frequency of heterozygous individuals is represented by
A) $p^2$
B) 2pq
C) pq
D) $q^2$
Explanation
[Solution] $p^2 + 2pq + q^2 = 1$; heterozygotes are 2pq. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.