Q. The temperature inside a refrigerator is $t_2$ °C and the room temperature is $t_1$ °C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
A) $\frac{t_1}{t_1 - t_2}$
B) $\frac{t_1 + 273}{t_1 - t_2}$
C) $\frac{t_2 + 273}{t_1 - t_2}$
D) $\frac{t_1 + t_2}{t_1 + 273}$
Explanation
[Solution] Heat delivered per joule $= \frac{Q_1}{W} = \frac{T_1}{T_1 - T_2} = \frac{t_1 + 273}{t_1 - t_2}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.