Q. A body of mass m is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3 s. When the mass m is increased by 1 kg, the time period of oscillations becomes 5 s. The value of m in kg is :
A) $\frac{3}{4}$
B) $\frac{4}{3}$
C) $\frac{16}{9}$
D) $\frac{9}{16}$
Explanation
[Solution] $T^2 \propto m$: $\frac{m + 1}{m} = \frac{25}{9}$, so m = 9/16 kg. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.