Q. The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L meter long. The length of the open pipe will be
A) L
B) 2L
C) $\frac{L}{2}$
D) 4L
Explanation
[Solution] $\frac{3v}{2L_0} = \frac{3v}{4L}$, so $L_0 = 2L$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.