Q. An electric dipole is placed at an angle of 30° with an electric field intensity $2 \times 10^5$ N/C. It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is

A) 8 mC
B) 2 mC
C) 5 mC
D) 7 μC
Explanation

[Solution] $\tau = qdE\sin\theta$: $q = \frac{4}{0.02 \times 2 \times 10^5 \times 0.5} = 2 \times 10^{-3}$ C. Answer (2).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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