Q. The molar conductivity of a 0.5 mol/$dm^3$ solution of $AgNO_3$ with electrolytic conductivity of $5.76 \times 10^{-3}$ S $cm^{-1}$ at 298 K is
A) 2.88 S $cm^2$/mol
B) 11.52 S $cm^2$/mol
C) 0.086 S $cm^2$/mol
D) 28.8 S $cm^2$/mol
Explanation
[Solution] $\Lambda_m = \frac{\kappa \times 1000}{M} = \frac{5.76 \times 10^{-3} \times 1000}{0.5} = 11.52$ S $cm^2$/mol. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.