Q. $AlF_3$ is soluble in HF only in presence of KF. It is due to the formation of
A) $K_3[AlF_3H_3]$
B) $K_3[AlF_6]$
C) $AlH_3$
D) $K[AlF_3H]$
Explanation
[Solution] $AlF_3 + 3KF \rightarrow K_3[AlF_6]$, a soluble complex. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.