Q. The hybridizations of atomic orbitals of nitrogen in $NO_2^+$, $NO_3^-$ and $NH_4^+$ respectively are
A) sp, $sp^3$ and $sp^2$
B) $sp^2$, $sp^3$ and sp
C) sp, $sp^2$ and $sp^3$
D) $sp^2$, sp and $sp^3$
Explanation
[Solution] $NO_2^+$ is linear (sp), $NO_3^-$ trigonal planar ($sp^2$), $NH_4^+$ tetrahedral ($sp^3$). Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.