Q. The correct geometry and hybridization for $XeF_4$ are :
A) Octahedral, $sp^3d^2$
B) Trigonal bipyramidal, $sp^3d$
C) Planar triangle, $sp^3d^3$
D) Square planar, $sp^3d^2$
Explanation
[Solution] Xe has 4 bond pairs and 2 lone pairs: $sp^3d^2$ with octahedral electron-pair geometry (molecular shape square planar). The official key accepted option (1), octahedral electron geometry. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.