Q. The cylindrical tube of a spray pump has radius R, one end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :
A) $\frac{V^2R}{nr}$
B) $\frac{VR^2}{n^2r^2}$
C) $\frac{VR^2}{nr^2}$
D) $\frac{VR^2}{n^3r^2}$
Explanation
[Solution] Continuity: $\pi R^2 V = n\pi r^2 v \Rightarrow v = \frac{VR^2}{nr^2}$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.