If vectors $\vec{A} = \cos\omega t\,\hat{i} + \sin\omega t\,\hat{j}$ and $\vec{B} = \cos\frac{\omega t}{2}\hat{i} + \sin\frac{\omega t}{2}\hat{j}$ are functions of time, then the value of t at which they are orthogonal to each other is :

Question

Dr. Abubacker · Accepted Answer

[Solution] $\vec{A}\cdot\vec{B} = \cos(\omega t - \frac{\omega t}{2}) = \cos\frac{\omega t}{2} = 0 \Rightarrow t = \frac{\pi}{\omega}$. Answer (4).

Q. If vectors $\vec{A} = \cos\omega t\,\hat{i} + \sin\omega t\,\hat{j}$ and $\vec{B} = \cos\frac{\omega t}{2}\hat{i} + \sin\frac{\omega t}{2}\hat{j}$ are functions of time, then the value of t at which they are orthogonal to each other is :

Explanation

Reviewed by Dr. Abubacker

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