A remote - sensing satellite of earth revolves in a circular orbit at a height of $0.25 imes 10^6$ m above the surface of earth. If earth's radius is $6.38 imes 10^6$ m and g = 9.8 $ms^{-2}$, then the orbital speed of the satellite is :

Question

A remote - sensing satellite of earth revolves in a circular orbit at a height of $0.25 	imes 10^6$ m above the surface of earth. If earth's radius is $6.38 	imes 10^6$ m and g = 9.8 $ms^{-2}$, then the orbital speed of the satellite is :

Dr. Abubacker · Accepted Answer

[Solution] $v = \sqrt{\frac{gR^2}{R+h}} = \sqrt{\frac{9.8 	imes (6.38	imes10^6)^2}{6.63	imes10^6}} \approx 7.76$ km/s. Answer (2).

Q. A remote - sensing satellite of earth revolves in a circular orbit at a height of $0.25 \times 10^6$ m above the surface of earth. If earth's radius is $6.38 \times 10^6$ m and g = 9.8 $ms^{-2}$, then the orbital speed of the satellite is :

Explanation

Reviewed by Dr. Abubacker

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