Q.
A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. The lowest resonant frequencies for this string is :
A) 105 Hz
B) 155 Hz
C) 205 Hz
D) 10.5 Hz
Explanation
[Solution] Consecutive harmonics differ by the fundamental: 420 − 315 = 105 Hz. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.