Two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius $\frac{r}{2}$ and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is :

Question

Dr. Abubacker · Accepted Answer

[Solution] $\frac{mv_1^2}{r} = \frac{2mv_2^2}{r/2} \Rightarrow v_1 = 2v_2$, so n = 2. Answer (2).

Q. Two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius $\frac{r}{2}$ and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is :

Explanation

Reviewed by Dr. Abubacker

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