A ball is thrown vertically downwards from a height of 20 m with an initial velocity $u_0$. It collides with the ground, loses 50 percent of its energy in collision and rebounds to the same height. The initial velocity $u_0$ is : (Take g = 10 $ms^{-2}$)

Question

Dr. Abubacker · Accepted Answer

[Solution] $\frac{1}{2}(\frac{1}{2}mu_0^2 + mgh) = mgh \Rightarrow u_0^2 = 2gh = 400$, so $u_0 = 20$ m/s. Answer (3).

Q. A ball is thrown vertically downwards from a height of 20 m with an initial velocity $u_0$. It collides with the ground, loses 50 percent of its energy in collision and rebounds to the same height. The initial velocity $u_0$ is : (Take g = 10 $ms^{-2}$)

Explanation

Reviewed by Dr. Abubacker

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