Q. If potential (in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz, the electric field (in N/C) at point (1,1,0) is :
A) $-(6\hat{i} + 9\hat{j} + \hat{k})$
B) $-(3\hat{i} + 5\hat{j} + 3\hat{k})$
C) $-(6\hat{i} + 5\hat{j} + 2\hat{k})$
D) $-(2\hat{i} + 3\hat{j} + \hat{k})$
Explanation
[Solution] $\vec{E} = -[6y\,\hat{i} + (6x - 1 + 2z)\hat{j} + 2y\,\hat{k}] = -(6\hat{i} + 5\hat{j} + 2\hat{k})$ at (1,1,0). Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.