Q. Two slits in Youngs experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, $\frac{I_{max}}{I_{min}}$ is :
A) $\frac{4}{9}$
B) $\frac{9}{4}$
C) $\frac{121}{49}$
D) $\frac{49}{121}$
Explanation
[Solution] $I_2/I_1 = 25$, so amplitudes are in ratio 5 : 1; $\frac{I_{max}}{I_{min}} = (\frac{5+1}{5-1})^2 = \frac{9}{4}$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.