Q. A proton and an alpha particle both enter a region of uniform magnetic field, B, moving at right angles to the field B. If the radius of circular orbits for both the particles is equal and the kinetic energy acquired by proton is 1 MeV, the energy acquired by the alpha particle will be :

A) 1 MeV
B) 4 MeV
C) 0.5 MeV
D) 1.5 MeV
Explanation

[Solution] $R = \frac{\sqrt{2mK}}{qB}$, so $K \propto \frac{q^2}{m}$, which is the same for proton and α (4/4): K = 1 MeV. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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