Q. If dimension of critical velocity $v_c$ of liquid flowing through a tube are expressed as $(\eta^x \rho^y r^z)$, where η, ρ and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by :
A) 1, 1, 1
B) 1, –1, –1
C) –1, –1, 1
D) –1, –1, –1
Explanation
[Solution] $[LT^{-1}] = [ML^{-1}T^{-1}]^x[ML^{-3}]^y[L]^z$ gives x = 1, y = –1, z = –1. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.