Q. The oscillation of a body on a smooth horizontal surface is represented by the equation, X = A cos(ωt), where X = displacement at time t, ω = frequency of oscillation. Which one of the following graphs shows correctly the variation of 'a' with 't'? (Here a = acceleration at time t, T = time period)
A) [image:2014_Q8_opt_a.png]
B) [image:2014_Q8_opt_b.png]
C) [image:2014_Q8_opt_c.png]
D) [image:2014_Q8_opt_d.png]
Explanation
[Solution] $a = -\omega^2 A\cos\omega t$: it starts at its negative maximum, reaches positive maximum at T/2 and returns to negative maximum at T, as in graph (3). Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.