Q. In a region the potential is represented by V(x, y, z) = 6x – 8xy – 8y + 6yz, where V is in volts and x, y, z are in meters. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is :

A) $6\sqrt{5}$ N
B) 30 N
C) 24 N
D) $4\sqrt{35}$ N
Explanation

[Solution] $\vec{E} = -[(6 - 8y)\hat{i} + (-8x - 8 + 6z)\hat{j} + 6y\hat{k}] = 2\hat{i} + 10\hat{j} - 6\hat{k}$ at (1,1,1); |E| = $\sqrt{140} = 2\sqrt{35}$, so F = $4\sqrt{35}$ N. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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